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Alberto Durán Pérez
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3482277Released 1y ago100% FreeIn Python 3.13, the behavior of the `locals()` function changed slightly in function scope. The main difference is: - In Python 3.12 and earlier, `locals()` would return a dict that was a snapshot of the local variables at the time it was called. - In Python 3.13, `locals()` returns a dict that dynamically reflects changes to local variables. This change makes the behavior of `locals()` in function scope more consistent with how it already worked in module and class scope. Here's an example to illustrate the difference: ```python def example_function(): x = 10 local_vars = locals() print(f"Initial locals: {local_vars}") x = 20 print(f"After changing x, locals: {local_vars}") local_vars['x'] = 30 print(f"After modifying locals dict, x: {x}") # Python 3.12 output: # Initial locals: {'x': 10} # After changing x, locals: {'x': 10} # After modifying locals dict, x: 20 # Python 3.13 output: # Initial locals: {'x': 10} # After changing x, locals: {'x': 20} # After modifying locals dict, x: 30 ``` In this example: 1. In Python 3.12, changing `x` doesn't affect the `local_vars` dict. 2. In Python 3.13, the `local_vars` dict reflects the new value of `x`. 3. In Python 3.12, modifying the `local_vars` dict doesn't affect the actual local variable `x`. 4. In Python 3.13, modifying the `local_vars` dict does change the value of `x`. This change can be particularly relevant when debugging or when writing introspection tools, as it provides a more accurate and up-to-date view of the local namespace.
